Base | Representation |
---|---|
bin | 100110110111010101110… |
… | …0011000011011100010001 |
3 | 200220122101212211202110120 |
4 | 1031232223203003130101 |
5 | 1200003414221121001 |
6 | 15205510031420453 |
7 | 1060624622422644 |
oct | 115565343033421 |
9 | 20818355752416 |
10 | 5341522442001 |
11 | 177a366190029 |
12 | 723281084729 |
13 | 2c991b4c4485 |
14 | 14676135ba5b |
15 | 93e2a396236 |
hex | 4dbab8c3711 |
5341522442001 has 4 divisors (see below), whose sum is σ = 7122029922672. Its totient is φ = 3561014961332.
The previous prime is 5341522441987. The next prime is 5341522442017. The reversal of 5341522442001 is 1002442251435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5341522442001 - 210 = 5341522440977 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5341522442101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 890253740331 + ... + 890253740336.
It is an arithmetic number, because the mean of its divisors is an integer number (1780507480668).
Almost surely, 25341522442001 is an apocalyptic number.
It is an amenable number.
5341522442001 is a deficient number, since it is larger than the sum of its proper divisors (1780507480671).
5341522442001 is a wasteful number, since it uses less digits than its factorization.
5341522442001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1780507480670.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 5341522442001 its reverse (1002442251435), we get a palindrome (6343964693436).
The spelling of 5341522442001 in words is "five trillion, three hundred forty-one billion, five hundred twenty-two million, four hundred forty-two thousand, one".
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