Base | Representation |
---|---|
bin | 11000010010110000101111… |
… | …10010010101111010001011 |
3 | 21000011000110102212101010201 |
4 | 30021120113302111322023 |
5 | 24000223110242104210 |
6 | 305341210031553031 |
7 | 14152361123232445 |
oct | 1411302762257213 |
9 | 230130412771121 |
10 | 53421202300555 |
11 | 16026894013401 |
12 | 5ba947868b777 |
13 | 23a67a038748b |
14 | d29858517495 |
15 | 62991c35a53a |
hex | 309617c95e8b |
53421202300555 has 16 divisors (see below), whose sum is σ = 68147526448800. Its totient is φ = 40086780249600.
The previous prime is 53421202300549. The next prime is 53421202300561. The reversal of 53421202300555 is 55500320212435.
53421202300555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (53421202300549) and next prime (53421202300561).
It is a de Polignac number, because none of the positive numbers 2k-53421202300555 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2783794590 + ... + 2783813779.
It is an arithmetic number, because the mean of its divisors is an integer number (4259220403050).
Almost surely, 253421202300555 is an apocalyptic number.
53421202300555 is a deficient number, since it is larger than the sum of its proper divisors (14726324148245).
53421202300555 is a wasteful number, since it uses less digits than its factorization.
53421202300555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5567608494.
The product of its (nonzero) digits is 180000, while the sum is 37.
The spelling of 53421202300555 in words is "fifty-three trillion, four hundred twenty-one billion, two hundred two million, three hundred thousand, five hundred fifty-five".
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