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53424015241 = 460311606347
BaseRepresentation
bin110001110000010100…
…011100011110001001
312002220012201011112011
4301300110130132021
51333403021441431
640313114015521
73600616431322
oct616024343611
9162805634464
1053424015241
1120725511413
12a42b7175a1
13506525374c
14282b38d449
1515ca292cb1
hexc7051c789

53424015241 has 4 divisors (see below), whose sum is σ = 53435626192. Its totient is φ = 53412404292.

The previous prime is 53424015221. The next prime is 53424015257. The reversal of 53424015241 is 14251042435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53424015241 - 211 = 53424013193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53424015221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5798571 + ... + 5807776.

It is an arithmetic number, because the mean of its divisors is an integer number (13358906548).

Almost surely, 253424015241 is an apocalyptic number.

It is an amenable number.

53424015241 is a deficient number, since it is larger than the sum of its proper divisors (11610951).

53424015241 is a wasteful number, since it uses less digits than its factorization.

53424015241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11610950.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 53424015241 its reverse (14251042435), we get a palindrome (67675057676).

The spelling of 53424015241 in words is "fifty-three billion, four hundred twenty-four million, fifteen thousand, two hundred forty-one".

Divisors: 1 4603 11606347 53424015241