Search a number
-
+
534335104325305 = 5106867020865061
BaseRepresentation
bin111100101111110011001011…
…0000101011001011010111001
32121001220221022010212121221101
41321133212112011121122321
51030014021243201402210
65132234054055411401
7220356303001334413
oct17137462605313271
92531827263777841
10534335104325305
1114528a277338988
124bb19881383b61
1319c1c77944a38a
1495d3d5818d9b3
1541b9437b2ca3a
hex1e5f9961596b9

534335104325305 has 4 divisors (see below), whose sum is σ = 641202125190372. Its totient is φ = 427468083460240.

The previous prime is 534335104325291. The next prime is 534335104325311. The reversal of 534335104325305 is 503523401533435.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 152365917508281 + 381969186817024 = 12343659^2 + 19544032^2 .

It is not a de Polignac number, because 534335104325305 - 221 = 534335102228153 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53433510432526 + ... + 53433510432535.

It is an arithmetic number, because the mean of its divisors is an integer number (160300531297593).

Almost surely, 2534335104325305 is an apocalyptic number.

It is an amenable number.

534335104325305 is a deficient number, since it is larger than the sum of its proper divisors (106867020865067).

534335104325305 is a wasteful number, since it uses less digits than its factorization.

534335104325305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106867020865066.

The product of its (nonzero) digits is 4860000, while the sum is 46.

The spelling of 534335104325305 in words is "five hundred thirty-four trillion, three hundred thirty-five billion, one hundred four million, three hundred twenty-five thousand, three hundred five".

Divisors: 1 5 106867020865061 534335104325305