Base | Representation |
---|---|
bin | 110001110001010010… |
… | …111100101010001011 |
3 | 12002221100112121012111 |
4 | 301301102330222023 |
5 | 1333421220300021 |
6 | 40314501123151 |
7 | 3601205622325 |
oct | 616122745213 |
9 | 162840477174 |
10 | 53440400011 |
11 | 20733792549 |
12 | a4350b94b7 |
13 | 506876c48b |
14 | 282d616615 |
15 | 15cb92c8e1 |
hex | c714bca8b |
53440400011 has 4 divisors (see below), whose sum is σ = 53484097392. Its totient is φ = 53396702632.
The previous prime is 53440400009. The next prime is 53440400017. The reversal of 53440400011 is 11000404435.
53440400011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11000404435 = 5 ⋅2200080887.
It is a cyclic number.
It is not a de Polignac number, because 53440400011 - 21 = 53440400009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53440400017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21846856 + ... + 21849301.
It is an arithmetic number, because the mean of its divisors is an integer number (13371024348).
Almost surely, 253440400011 is an apocalyptic number.
53440400011 is a deficient number, since it is larger than the sum of its proper divisors (43697381).
53440400011 is a wasteful number, since it uses less digits than its factorization.
53440400011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43697380.
The product of its (nonzero) digits is 960, while the sum is 22.
Adding to 53440400011 its reverse (11000404435), we get a palindrome (64440804446).
The spelling of 53440400011 in words is "fifty-three billion, four hundred forty million, four hundred thousand, eleven".
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