Base | Representation |
---|---|
bin | 111100110000011111100011… |
… | …0011000111011111110000011 |
3 | 2121002021001021202002110021001 |
4 | 1321200333012120323332003 |
5 | 1030022101431413100220 |
6 | 5132345534355112431 |
7 | 220366215422444116 |
oct | 17140770630737603 |
9 | 2532231252073231 |
10 | 534430404034435 |
11 | 145316730561977 |
12 | 4bb34238ba2717 |
13 | 19c287562267cc |
14 | 95d87d8c8857d |
15 | 41bbb643b380a |
hex | 1e60fc663bf83 |
534430404034435 has 4 divisors (see below), whose sum is σ = 641316484841328. Its totient is φ = 427544323227544.
The previous prime is 534430404034421. The next prime is 534430404034487.
534430404034435 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 534430404034435 - 223 = 534430395645827 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53443040403439 + ... + 53443040403448.
It is an arithmetic number, because the mean of its divisors is an integer number (160329121210332).
Almost surely, 2534430404034435 is an apocalyptic number.
534430404034435 is a deficient number, since it is larger than the sum of its proper divisors (106886080806893).
534430404034435 is a wasteful number, since it uses less digits than its factorization.
534430404034435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106886080806892.
The product of its (nonzero) digits is 8294400, while the sum is 46.
It can be divided in two parts, 53443040 and 4034435, that added together give a palindrome (57477475).
The spelling of 534430404034435 in words is "five hundred thirty-four trillion, four hundred thirty billion, four hundred four million, thirty-four thousand, four hundred thirty-five".
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