Base | Representation |
---|---|
bin | 110001110001011101… |
… | …101000010010010001 |
3 | 12002221112210212021011 |
4 | 301301131220102101 |
5 | 1333422424401040 |
6 | 40315041130521 |
7 | 3601241464066 |
oct | 616135502221 |
9 | 162845725234 |
10 | 53443200145 |
11 | 20735325305 |
12 | a436029a41 |
13 | 506920cb6a |
14 | 282db44c6d |
15 | 15cbcd23ea |
hex | c71768491 |
53443200145 has 4 divisors (see below), whose sum is σ = 64131840180. Its totient is φ = 42754560112.
The previous prime is 53443200137. The next prime is 53443200149. The reversal of 53443200145 is 54100234435.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 37571231889 + 15871968256 = 193833^2 + 125984^2 .
It is a cyclic number.
It is not a de Polignac number, because 53443200145 - 23 = 53443200137 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53443200149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5344320010 + ... + 5344320019.
It is an arithmetic number, because the mean of its divisors is an integer number (16032960045).
Almost surely, 253443200145 is an apocalyptic number.
It is an amenable number.
53443200145 is a deficient number, since it is larger than the sum of its proper divisors (10688640035).
53443200145 is a wasteful number, since it uses less digits than its factorization.
53443200145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10688640034.
The product of its (nonzero) digits is 28800, while the sum is 31.
The spelling of 53443200145 in words is "fifty-three billion, four hundred forty-three million, two hundred thousand, one hundred forty-five".
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