Base | Representation |
---|---|
bin | 11000010011011011101010… |
… | …01100011000011111010011 |
3 | 21000020012221021100101220121 |
4 | 30021231311030120133103 |
5 | 24001112303011310220 |
6 | 305355540304451111 |
7 | 14154135123434422 |
oct | 1411556514303723 |
9 | 230205837311817 |
10 | 53444244244435 |
11 | 16035638650930 |
12 | 5bb1a29319a97 |
13 | 23a8a03040bb5 |
14 | d2aa028032b9 |
15 | 62a31a1a2eaa |
hex | 309b753187d3 |
53444244244435 has 16 divisors (see below), whose sum is σ = 70100826922080. Its totient is φ = 38792178691840.
The previous prime is 53444244244411. The next prime is 53444244244471.
53444244244435 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53444244244435 - 217 = 53444244113363 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 954503962 + ... + 954559951.
It is an arithmetic number, because the mean of its divisors is an integer number (4381301682630).
Almost surely, 253444244244435 is an apocalyptic number.
53444244244435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53444244244435 is a deficient number, since it is larger than the sum of its proper divisors (16656582677645).
53444244244435 is a wasteful number, since it uses less digits than its factorization.
53444244244435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1909064438.
The product of its digits is 58982400, while the sum is 52.
It can be divided in two parts, 5344424 and 4244435, that added together give a palindrome (9588859).
The spelling of 53444244244435 in words is "fifty-three trillion, four hundred forty-four billion, two hundred forty-four million, two hundred forty-four thousand, four hundred thirty-five".
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