Base | Representation |
---|---|
bin | 100110111000110011001… |
… | …0101100101010100101001 |
3 | 200220221111021122201002011 |
4 | 1031301212111211110221 |
5 | 1200031324000001103 |
6 | 15211145020035521 |
7 | 1061065364356603 |
oct | 115614625452451 |
9 | 20827437581064 |
10 | 5344656250153 |
11 | 1780724133520 |
12 | 7239b6692ba1 |
13 | 2c9cca82891c |
14 | 14697b636173 |
15 | 9406056bd6d |
hex | 4dc66565529 |
5344656250153 has 4 divisors (see below), whose sum is σ = 5830534091088. Its totient is φ = 4858778409220.
The previous prime is 5344656250133. The next prime is 5344656250207. The reversal of 5344656250153 is 3510526564435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5344656250153 - 213 = 5344656241961 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5344656250097 and 5344656250106.
It is not an unprimeable number, because it can be changed into a prime (5344656250133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242938920451 + ... + 242938920472.
It is an arithmetic number, because the mean of its divisors is an integer number (1457633522772).
Almost surely, 25344656250153 is an apocalyptic number.
It is an amenable number.
5344656250153 is a deficient number, since it is larger than the sum of its proper divisors (485877840935).
5344656250153 is a wasteful number, since it uses less digits than its factorization.
5344656250153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 485877840934.
The product of its (nonzero) digits is 6480000, while the sum is 49.
The spelling of 5344656250153 in words is "five trillion, three hundred forty-four billion, six hundred fifty-six million, two hundred fifty thousand, one hundred fifty-three".
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