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5347713444121 = 36809145282769
BaseRepresentation
bin100110111010001110010…
…0011110110100100011001
3200221020101100022020210101
41031310130203312210121
51200104104120202441
615212412230215401
71061234216161546
oct115643443664431
920836340266711
105347713444121
111781a52908604
1272450a4b4561
132ca397016b39
14146b8b689bcd
159418db5c231
hex4dd1c8f6919

5347713444121 has 4 divisors (see below), whose sum is σ = 5347858763700. Its totient is φ = 5347568124544.

The previous prime is 5347713444089. The next prime is 5347713444167. The reversal of 5347713444121 is 1214443177435.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1009703425600 + 4338010018521 = 1004840^2 + 2082789^2 .

It is a cyclic number.

It is not a de Polignac number, because 5347713444121 - 25 = 5347713444089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5347713444421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72604576 + ... + 72678193.

It is an arithmetic number, because the mean of its divisors is an integer number (1336964690925).

Almost surely, 25347713444121 is an apocalyptic number.

It is an amenable number.

5347713444121 is a deficient number, since it is larger than the sum of its proper divisors (145319579).

5347713444121 is a wasteful number, since it uses less digits than its factorization.

5347713444121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145319578.

The product of its digits is 1128960, while the sum is 46.

The spelling of 5347713444121 in words is "five trillion, three hundred forty-seven billion, seven hundred thirteen million, four hundred forty-four thousand, one hundred twenty-one".

Divisors: 1 36809 145282769 5347713444121