Base | Representation |
---|---|
bin | 1111100100010101001… |
… | …11000011101110000011 |
3 | 1220010200012102112101212 |
4 | 13302022213003232003 |
5 | 32230434232024423 |
6 | 1045421430120335 |
7 | 53434233134024 |
oct | 7621247035603 |
9 | 1803605375355 |
10 | 534901439363 |
11 | 196939a10465 |
12 | 878014b00ab |
13 | 3b596b13145 |
14 | 1bc645d4c4b |
15 | dda9be5578 |
hex | 7c8a9c3b83 |
534901439363 has 4 divisors (see below), whose sum is σ = 534967476528. Its totient is φ = 534835402200.
The previous prime is 534901439357. The next prime is 534901439389. The reversal of 534901439363 is 363934109435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-534901439363 is a prime.
It is a super-2 number, since 2×5349014393632 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534901439353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33006431 + ... + 33022632.
It is an arithmetic number, because the mean of its divisors is an integer number (133741869132).
Almost surely, 2534901439363 is an apocalyptic number.
534901439363 is a deficient number, since it is larger than the sum of its proper divisors (66037165).
534901439363 is an equidigital number, since it uses as much as digits as its factorization.
534901439363 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66037164.
The product of its (nonzero) digits is 3149280, while the sum is 50.
The spelling of 534901439363 in words is "five hundred thirty-four billion, nine hundred one million, four hundred thirty-nine thousand, three hundred sixty-three".
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