Base | Representation |
---|---|
bin | 110001110100110111… |
… | …110111100100010011 |
3 | 12010002112110102121112 |
4 | 301310313313210103 |
5 | 1334032101111011 |
6 | 40324443243535 |
7 | 3602534661050 |
oct | 616467674423 |
9 | 163075412545 |
10 | 53500410131 |
11 | 2076464aa93 |
12 | a4512195ab |
13 | 5078020c1c |
14 | 2837598027 |
15 | 15d1d3358b |
hex | c74df7913 |
53500410131 has 16 divisors (see below), whose sum is σ = 62325884160. Its totient is φ = 44979064800.
The previous prime is 53500410109. The next prime is 53500410151. The reversal of 53500410131 is 13101400535.
It is a cyclic number.
It is not a de Polignac number, because 53500410131 - 226 = 53433301267 is a prime.
It is a super-2 number, since 2×535004101312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53500410097 and 53500410106.
It is not an unprimeable number, because it can be changed into a prime (53500410151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 277961 + ... + 429258.
It is an arithmetic number, because the mean of its divisors is an integer number (3895367760).
Almost surely, 253500410131 is an apocalyptic number.
53500410131 is a deficient number, since it is larger than the sum of its proper divisors (8825474029).
53500410131 is a wasteful number, since it uses less digits than its factorization.
53500410131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 707434.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 53500410131 its reverse (13101400535), we get a palindrome (66601810666).
The spelling of 53500410131 in words is "fifty-three billion, five hundred million, four hundred ten thousand, one hundred thirty-one".
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