Base | Representation |
---|---|
bin | 11000010101001011111111… |
… | …11100110100000010110001 |
3 | 21000102222121101021100112120 |
4 | 30022211333330310002301 |
5 | 24003104311342121023 |
6 | 305443353005344453 |
7 | 14161401506162535 |
oct | 1412457774640261 |
9 | 230388541240476 |
10 | 53504554254513 |
11 | 1605917701a06a |
12 | 600165ab68129 |
13 | 23b15c4a921ab |
14 | d2d8c4513bc5 |
15 | 62bb99c408e3 |
hex | 30a97ff340b1 |
53504554254513 has 4 divisors (see below), whose sum is σ = 71339405672688. Its totient is φ = 35669702836340.
The previous prime is 53504554254511. The next prime is 53504554254553. The reversal of 53504554254513 is 31545245540535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53504554254513 - 21 = 53504554254511 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53504554254511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8917425709083 + ... + 8917425709088.
It is an arithmetic number, because the mean of its divisors is an integer number (17834851418172).
Almost surely, 253504554254513 is an apocalyptic number.
It is an amenable number.
53504554254513 is a deficient number, since it is larger than the sum of its proper divisors (17834851418175).
53504554254513 is a wasteful number, since it uses less digits than its factorization.
53504554254513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17834851418174.
The product of its (nonzero) digits is 18000000, while the sum is 51.
The spelling of 53504554254513 in words is "fifty-three trillion, five hundred four billion, five hundred fifty-four million, two hundred fifty-four thousand, five hundred thirteen".
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