Base | Representation |
---|---|
bin | 11000010101001101011001… |
… | …00110011001001110111011 |
3 | 21000110001112120211110110020 |
4 | 30022212230212121032323 |
5 | 24003112330124233001 |
6 | 305443555205221523 |
7 | 14161426203333132 |
oct | 1412465446311673 |
9 | 230401476743406 |
10 | 53505303352251 |
11 | 16059520953303 |
12 | 6001829a018a3 |
13 | 23b16b40320aa |
14 | d2d955bcc919 |
15 | 62bbe08b0736 |
hex | 30a9ac9993bb |
53505303352251 has 4 divisors (see below), whose sum is σ = 71340404469672. Its totient is φ = 35670202234832.
The previous prime is 53505303352243. The next prime is 53505303352261. The reversal of 53505303352251 is 15225330350535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53505303352251 - 23 = 53505303352243 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53505303352211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8917550558706 + ... + 8917550558711.
It is an arithmetic number, because the mean of its divisors is an integer number (17835101117418).
Almost surely, 253505303352251 is an apocalyptic number.
53505303352251 is a deficient number, since it is larger than the sum of its proper divisors (17835101117421).
53505303352251 is a wasteful number, since it uses less digits than its factorization.
53505303352251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17835101117420.
The product of its (nonzero) digits is 1012500, while the sum is 42.
The spelling of 53505303352251 in words is "fifty-three trillion, five hundred five billion, three hundred three million, three hundred fifty-two thousand, two hundred fifty-one".
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