Base | Representation |
---|---|
bin | 11000010101101001100001… |
… | …01101001011110001111011 |
3 | 21000111111112000112200100221 |
4 | 30022310300231023301323 |
5 | 24003334242041022210 |
6 | 305454533502040511 |
7 | 14162502343132666 |
oct | 1412646055136173 |
9 | 230444460480327 |
10 | 53520404626555 |
11 | 16064970157199 |
12 | 6004743279137 |
13 | 23b2c4c849969 |
14 | d305896566dd |
15 | 62c2c652c1da |
hex | 30ad30b4bc7b |
53520404626555 has 16 divisors (see below), whose sum is σ = 65463874731360. Its totient is φ = 41993416217088.
The previous prime is 53520404626529. The next prime is 53520404626627. The reversal of 53520404626555 is 55562640402535.
It is a cyclic number.
It is not a de Polignac number, because 53520404626555 - 25 = 53520404626523 is a prime.
It is a super-2 number, since 2×535204046265552 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209370072 + ... + 209625541.
It is an arithmetic number, because the mean of its divisors is an integer number (4091492170710).
Almost surely, 253520404626555 is an apocalyptic number.
53520404626555 is a deficient number, since it is larger than the sum of its proper divisors (11943470104805).
53520404626555 is a wasteful number, since it uses less digits than its factorization.
53520404626555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418996110.
The product of its (nonzero) digits is 21600000, while the sum is 52.
The spelling of 53520404626555 in words is "fifty-three trillion, five hundred twenty billion, four hundred four million, six hundred twenty-six thousand, five hundred fifty-five".
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