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535305400214513 = 2743719510347349
BaseRepresentation
bin111100110110110111000000…
…0001110011110001111110001
32121012100200210201202212201212
41321231232000032132033301
51030130420424423331023
65134255523404005505
7220516352561323355
oct17155560016361761
92535320721685655
10535305400214513
11145623822046785
1250055933530895
1319c9010c73c7a6
149628cc35b1465
1541d47c6715e78
hex1e6db8039e3f1

535305400214513 has 4 divisors (see below), whose sum is σ = 535324910589300. Its totient is φ = 535285889839728.

The previous prime is 535305400214509. The next prime is 535305400214539. The reversal of 535305400214513 is 315412004503535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 427744793088064 + 107560607126449 = 20681992^2 + 10371143^2 .

It is a cyclic number.

It is not a de Polignac number, because 535305400214513 - 22 = 535305400214509 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (535305400214503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9755146238 + ... + 9755201111.

It is an arithmetic number, because the mean of its divisors is an integer number (133831227647325).

Almost surely, 2535305400214513 is an apocalyptic number.

It is an amenable number.

535305400214513 is a deficient number, since it is larger than the sum of its proper divisors (19510374787).

535305400214513 is a wasteful number, since it uses less digits than its factorization.

535305400214513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19510374786.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 535305400214513 in words is "five hundred thirty-five trillion, three hundred five billion, four hundred million, two hundred fourteen thousand, five hundred thirteen".

Divisors: 1 27437 19510347349 535305400214513