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5353413101113 = 71169524845469
BaseRepresentation
bin100110111100111000001…
…0010010100011000111001
3200221210002120012211022111
41031321300102110120321
51200202242223213423
615215153553452321
71061525365361410
oct115716022243071
920853076184274
105353413101113
111784408150230
1272563b2710a1
132caa94ac493c
1414716c636477
15943c421960d
hex4de70494639

5353413101113 has 8 divisors (see below), whose sum is σ = 6674385165120. Its totient is φ = 4171490728080.

The previous prime is 5353413101077. The next prime is 5353413101161. The reversal of 5353413101113 is 3111013143535.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5353413101113 - 29 = 5353413100601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5353413101173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34762422658 + ... + 34762422811.

It is an arithmetic number, because the mean of its divisors is an integer number (834298145640).

Almost surely, 25353413101113 is an apocalyptic number.

It is an amenable number.

5353413101113 is a deficient number, since it is larger than the sum of its proper divisors (1320972064007).

5353413101113 is a wasteful number, since it uses less digits than its factorization.

5353413101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69524845487.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 5353413101113 its reverse (3111013143535), we get a palindrome (8464426244648).

The spelling of 5353413101113 in words is "five trillion, three hundred fifty-three billion, four hundred thirteen million, one hundred one thousand, one hundred thirteen".

Divisors: 1 7 11 77 69524845469 486673918283 764773300159 5353413101113