Base | Representation |
---|---|
bin | 110001110110111010… |
… | …000110110110001001 |
3 | 12010011220200222200012 |
4 | 301312322012312021 |
5 | 1334114321121213 |
6 | 40332103121305 |
7 | 3603431115266 |
oct | 616672066611 |
9 | 163156628605 |
10 | 53534551433 |
11 | 20781949940 |
12 | a460743235 |
13 | 5082115b8c |
14 | 283bd2426d |
15 | 15d4d294a8 |
hex | c76e86d89 |
53534551433 has 4 divisors (see below), whose sum is σ = 58401328848. Its totient is φ = 48667774020.
The previous prime is 53534551337. The next prime is 53534551451. The reversal of 53534551433 is 33415543535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53534551433 - 210 = 53534550409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53534551033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2433388691 + ... + 2433388712.
It is an arithmetic number, because the mean of its divisors is an integer number (14600332212).
Almost surely, 253534551433 is an apocalyptic number.
It is an amenable number.
53534551433 is a deficient number, since it is larger than the sum of its proper divisors (4866777415).
53534551433 is a wasteful number, since it uses less digits than its factorization.
53534551433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4866777414.
The product of its digits is 810000, while the sum is 41.
The spelling of 53534551433 in words is "fifty-three billion, five hundred thirty-four million, five hundred fifty-one thousand, four hundred thirty-three".
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