Search a number
-
+
53534551433 = 114866777403
BaseRepresentation
bin110001110110111010…
…000110110110001001
312010011220200222200012
4301312322012312021
51334114321121213
640332103121305
73603431115266
oct616672066611
9163156628605
1053534551433
1120781949940
12a460743235
135082115b8c
14283bd2426d
1515d4d294a8
hexc76e86d89

53534551433 has 4 divisors (see below), whose sum is σ = 58401328848. Its totient is φ = 48667774020.

The previous prime is 53534551337. The next prime is 53534551451. The reversal of 53534551433 is 33415543535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53534551433 - 210 = 53534550409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53534551033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2433388691 + ... + 2433388712.

It is an arithmetic number, because the mean of its divisors is an integer number (14600332212).

Almost surely, 253534551433 is an apocalyptic number.

It is an amenable number.

53534551433 is a deficient number, since it is larger than the sum of its proper divisors (4866777415).

53534551433 is a wasteful number, since it uses less digits than its factorization.

53534551433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4866777414.

The product of its digits is 810000, while the sum is 41.

The spelling of 53534551433 in words is "fifty-three billion, five hundred thirty-four million, five hundred fifty-one thousand, four hundred thirty-three".

Divisors: 1 11 4866777403 53534551433