Base | Representation |
---|---|
bin | 111100110111101111100010… |
… | …0011110010110100111010011 |
3 | 2121012210022011121000001121121 |
4 | 1321233133010132112213103 |
5 | 1030134413043401000111 |
6 | 5134431402255103111 |
7 | 220531211230200115 |
oct | 17157370436264723 |
9 | 2535708147001547 |
10 | 535426804312531 |
11 | 14567026153948a |
12 | 50075375511a97 |
13 | 19c9b6b97ab991 |
14 | 9630b1d1b53b5 |
15 | 41d7a2eac0871 |
hex | 1e6f7c47969d3 |
535426804312531 has 16 divisors (see below), whose sum is σ = 540332799552000. Its totient is φ = 530538432098400.
The previous prime is 535426804312489. The next prime is 535426804312601. The reversal of 535426804312531 is 135213408624535.
It is a cyclic number.
It is not a de Polignac number, because 535426804312531 - 239 = 534877048498643 is a prime.
It is a super-2 number, since 2×5354268043125312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (535426804312331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1365232336 + ... + 1365624466.
It is an arithmetic number, because the mean of its divisors is an integer number (33770799972000).
Almost surely, 2535426804312531 is an apocalyptic number.
535426804312531 is a deficient number, since it is larger than the sum of its proper divisors (4905995239469).
535426804312531 is a wasteful number, since it uses less digits than its factorization.
535426804312531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414570.
The product of its (nonzero) digits is 10368000, while the sum is 52.
The spelling of 535426804312531 in words is "five hundred thirty-five trillion, four hundred twenty-six billion, eight hundred four million, three hundred twelve thousand, five hundred thirty-one".
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