Base | Representation |
---|---|
bin | 11000010110010100100110… |
… | …01010011110111111000011 |
3 | 21000120201012202110222101212 |
4 | 30023022103022132333003 |
5 | 24004224123003423133 |
6 | 305513320403120335 |
7 | 14164251422534054 |
oct | 1413122312367703 |
9 | 230521182428355 |
10 | 53543531311043 |
11 | 16073758603584 |
12 | 60091183730ab |
13 | 23b5196c33457 |
14 | d31740cc072b |
15 | 62cbcba13148 |
hex | 30b29329efc3 |
53543531311043 has 4 divisors (see below), whose sum is σ = 55270741998528. Its totient is φ = 51816320623560.
The previous prime is 53543531311031. The next prime is 53543531311163. The reversal of 53543531311043 is 34011313534535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53543531311043 - 210 = 53543531310019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53543531311003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 863605343696 + ... + 863605343757.
It is an arithmetic number, because the mean of its divisors is an integer number (13817685499632).
Almost surely, 253543531311043 is an apocalyptic number.
53543531311043 is a deficient number, since it is larger than the sum of its proper divisors (1727210687485).
53543531311043 is a wasteful number, since it uses less digits than its factorization.
53543531311043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1727210687484.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 53543531311043 its reverse (34011313534535), we get a palindrome (87554844845578).
The spelling of 53543531311043 in words is "fifty-three trillion, five hundred forty-three billion, five hundred thirty-one million, three hundred eleven thousand, forty-three".
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