Base | Representation |
---|---|
bin | 100110111101010101111… |
… | …0010111111010110101011 |
3 | 200221212200010220211112112 |
4 | 1031322223302333112223 |
5 | 1200211313322141301 |
6 | 15215441021232535 |
7 | 1061562210663026 |
oct | 115725362772653 |
9 | 20855603824475 |
10 | 5354411521451 |
11 | 178487a795203 |
12 | 72587970274b |
13 | 2cabc38caac5 |
14 | 1472250921bd |
15 | 94431bd79bb |
hex | 4deabcbf5ab |
5354411521451 has 4 divisors (see below), whose sum is σ = 5429825768304. Its totient is φ = 5278997274600.
The previous prime is 5354411521441. The next prime is 5354411521519. The reversal of 5354411521451 is 1541251144535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5354411521451 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5354411521399 and 5354411521408.
It is not an unprimeable number, because it can be changed into a prime (5354411521441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37707123320 + ... + 37707123461.
It is an arithmetic number, because the mean of its divisors is an integer number (1357456442076).
Almost surely, 25354411521451 is an apocalyptic number.
5354411521451 is a deficient number, since it is larger than the sum of its proper divisors (75414246853).
5354411521451 is an equidigital number, since it uses as much as digits as its factorization.
5354411521451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75414246852.
The product of its digits is 240000, while the sum is 41.
Adding to 5354411521451 its reverse (1541251144535), we get a palindrome (6895662665986).
The spelling of 5354411521451 in words is "five trillion, three hundred fifty-four billion, four hundred eleven million, five hundred twenty-one thousand, four hundred fifty-one".
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