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53550453131 = 77650064733
BaseRepresentation
bin110001110111110110…
…110001000110001011
312010020000121212200222
4301313312301012023
51334132404000011
640333432020255
73604013225030
oct616766610613
9163200555628
1053550453131
112078a92003a
12a465b3168b
1350854c2a76
1428400a3387
1515d641addb
hexc77db118b

53550453131 has 4 divisors (see below), whose sum is σ = 61200517872. Its totient is φ = 45900388392.

The previous prime is 53550453109. The next prime is 53550453137. The reversal of 53550453131 is 13135405535.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53550453131 - 218 = 53550190987 is a prime.

It is a super-3 number, since 3×535504531313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53550453091 and 53550453100.

It is not an unprimeable number, because it can be changed into a prime (53550453137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3825032360 + ... + 3825032373.

It is an arithmetic number, because the mean of its divisors is an integer number (15300129468).

Almost surely, 253550453131 is an apocalyptic number.

53550453131 is a deficient number, since it is larger than the sum of its proper divisors (7650064741).

53550453131 is an equidigital number, since it uses as much as digits as its factorization.

53550453131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7650064740.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 53550453131 its reverse (13135405535), we get a palindrome (66685858666).

The spelling of 53550453131 in words is "fifty-three billion, five hundred fifty million, four hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 7 7650064733 53550453131