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5355530530603 = 11486866411873
BaseRepresentation
bin100110111101110111001…
…1111101010111100101011
3200221222120010112101111221
41031323232133222330223
51200221111303434403
615220144033402511
71061632016260261
oct115735637527453
920858503471457
105355530530603
1117852a4403360
12725b30409437
132cb0416a5bb6
141472cd93c431
159449a075dbd
hex4deee7eaf2b

5355530530603 has 4 divisors (see below), whose sum is σ = 5842396942488. Its totient is φ = 4868664118720.

The previous prime is 5355530530601. The next prime is 5355530530663. The reversal of 5355530530603 is 3060350355535.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5355530530603 - 21 = 5355530530601 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5355530530603.

It is not an unprimeable number, because it can be changed into a prime (5355530530601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243433205926 + ... + 243433205947.

It is an arithmetic number, because the mean of its divisors is an integer number (1460599235622).

Almost surely, 25355530530603 is an apocalyptic number.

5355530530603 is a deficient number, since it is larger than the sum of its proper divisors (486866411885).

5355530530603 is a wasteful number, since it uses less digits than its factorization.

5355530530603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 486866411884.

The product of its (nonzero) digits is 1518750, while the sum is 43.

The spelling of 5355530530603 in words is "five trillion, three hundred fifty-five billion, five hundred thirty million, five hundred thirty thousand, six hundred three".

Divisors: 1 11 486866411873 5355530530603