Base | Representation |
---|---|
bin | 110001111001010000… |
… | …101001000001001001 |
3 | 12010021122221211202202 |
4 | 301321100221001021 |
5 | 1334204421404001 |
6 | 40340033005545 |
7 | 3604420411505 |
oct | 617120510111 |
9 | 163248854682 |
10 | 53574013001 |
11 | 207a2151a03 |
12 | a4719b38b5 |
13 | 508a351612 |
14 | 2843277305 |
15 | 15d852196b |
hex | c79429049 |
53574013001 has 4 divisors (see below), whose sum is σ = 53583416004. Its totient is φ = 53564610000.
The previous prime is 53574012937. The next prime is 53574013007. The reversal of 53574013001 is 10031047535.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 42404693776 + 11169319225 = 205924^2 + 105685^2 .
It is a cyclic number.
It is not a de Polignac number, because 53574013001 - 26 = 53574012937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53574013007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4692950 + ... + 4704351.
It is an arithmetic number, because the mean of its divisors is an integer number (13395854001).
Almost surely, 253574013001 is an apocalyptic number.
It is an amenable number.
53574013001 is a deficient number, since it is larger than the sum of its proper divisors (9403003).
53574013001 is an equidigital number, since it uses as much as digits as its factorization.
53574013001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9403002.
The product of its (nonzero) digits is 6300, while the sum is 29.
The spelling of 53574013001 in words is "fifty-three billion, five hundred seventy-four million, thirteen thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •