536113 has 4 divisors (see below), whose sum is σ = 537588. Its totient is φ = 534640.

The previous prime is 536111. The next prime is 536141. The reversal of 536113 is 311635.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311635 = 5 ⋅62327.

It can be written as a sum of positive squares in 2 ways, for example, as 135424 + 400689 = 368^2 + 633^2 .

It is a cyclic number.

It is not a de Polignac number, because 536113 - 2¹ = 536111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (536111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243 + ... + 1063.

It is an arithmetic number, because the mean of its divisors is an integer number (134397).

2⁵³⁶¹¹³ is an apocalyptic number.

It is an amenable number.

536113 is a deficient number, since it is larger than the sum of its proper divisors (1475).

536113 is an equidigital number, since it uses as much as digits as its factorization.

536113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1474.

The product of its digits is 270, while the sum is 19.

The square root of 536113 is about 732.1973777609. The cubic root of 536113 is about 81.2366700025.

Adding to 536113 its reverse (311635), we get a palindrome (847748).

The spelling of 536113 in words is "five hundred thirty-six thousand, one hundred thirteen".