Base | Representation |
---|---|
bin | 1001111111001001… |
… | …01010100100001001 |
3 | 111211122200121220201 |
4 | 10333210222210021 |
5 | 41440023342213 |
6 | 2244004252201 |
7 | 246602236651 |
oct | 47744524411 |
9 | 14748617821 |
10 | 5361543433 |
11 | 23014a6a34 |
12 | 10576a1061 |
13 | 675a2700c |
14 | 38c0d5361 |
15 | 215a706dd |
hex | 13f92a909 |
5361543433 has 4 divisors (see below), whose sum is σ = 5364931968. Its totient is φ = 5358154900.
The previous prime is 5361543427. The next prime is 5361543491. The reversal of 5361543433 is 3343451635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5361543433 - 25 = 5361543401 is a prime.
It is a super-2 number, since 2×53615434332 = 57492295967890850978, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5361543392 and 5361543401.
It is not an unprimeable number, because it can be changed into a prime (5361543233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1691893 + ... + 1695058.
It is an arithmetic number, because the mean of its divisors is an integer number (1341232992).
Almost surely, 25361543433 is an apocalyptic number.
It is an amenable number.
5361543433 is a deficient number, since it is larger than the sum of its proper divisors (3388535).
5361543433 is a wasteful number, since it uses less digits than its factorization.
5361543433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3388534.
The product of its digits is 194400, while the sum is 37.
The square root of 5361543433 is about 73222.5609563064. The cubic root of 5361543433 is about 1750.2359880939.
The spelling of 5361543433 in words is "five billion, three hundred sixty-one million, five hundred forty-three thousand, four hundred thirty-three".
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