Base | Representation |
---|---|
bin | 11000011000111100010111… |
… | …11111111101100110100011 |
3 | 21000220022201011211002112201 |
4 | 30030132023333331212203 |
5 | 24012213110442104241 |
6 | 310022534352034031 |
7 | 14203620512062003 |
oct | 1414361377754643 |
9 | 230808634732481 |
10 | 53633605425571 |
11 | 160a8980045a46 |
12 | 6022675b32917 |
13 | 23c0820204c82 |
14 | d35c47992003 |
15 | 6301ee62e931 |
hex | 30c78bffd9a3 |
53633605425571 has 8 divisors (see below), whose sum is σ = 53645777397440. Its totient is φ = 53621434824768.
The previous prime is 53633605425539. The next prime is 53633605425623. The reversal of 53633605425571 is 17552450633635.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53633605425571 - 25 = 53633605425539 is a prime.
It is a super-3 number, since 3×536336054255713 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53633605423571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80026255 + ... + 80693671.
It is an arithmetic number, because the mean of its divisors is an integer number (6705722174680).
Almost surely, 253633605425571 is an apocalyptic number.
53633605425571 is a deficient number, since it is larger than the sum of its proper divisors (12171971869).
53633605425571 is a wasteful number, since it uses less digits than its factorization.
53633605425571 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 685533.
The product of its (nonzero) digits is 34020000, while the sum is 55.
The spelling of 53633605425571 in words is "fifty-three trillion, six hundred thirty-three billion, six hundred five million, four hundred twenty-five thousand, five hundred seventy-one".
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