Base | Representation |
---|---|
bin | 1100110010011… |
… | …0010101100011 |
3 | 10201220220120101 |
4 | 3030212111203 |
5 | 102212300103 |
6 | 5153323231 |
7 | 1220612344 |
oct | 314462543 |
9 | 121826511 |
10 | 53634403 |
11 | 28303359 |
12 | 15b66517 |
13 | b15b744 |
14 | 71a20cb |
15 | 4a96a1d |
hex | 3326563 |
53634403 has 4 divisors (see below), whose sum is σ = 53707720. Its totient is φ = 53561088.
The previous prime is 53634389. The next prime is 53634419. The reversal of 53634403 is 30443635.
53634403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30443635 = 5 ⋅6088727.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53634403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53634703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35550 + ... + 37027.
It is an arithmetic number, because the mean of its divisors is an integer number (13426930).
Almost surely, 253634403 is an apocalyptic number.
53634403 is a deficient number, since it is larger than the sum of its proper divisors (73317).
53634403 is an equidigital number, since it uses as much as digits as its factorization.
53634403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73316.
The product of its (nonzero) digits is 12960, while the sum is 28.
The square root of 53634403 is about 7323.5512560506. The cubic root of 53634403 is about 377.1213764398.
The spelling of 53634403 in words is "fifty-three million, six hundred thirty-four thousand, four hundred three".
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