Base | Representation |
---|---|
bin | 1111100111001010011… |
… | …10000101110110001011 |
3 | 1220021121010220202202022 |
4 | 13303211032011312023 |
5 | 32242042413334011 |
6 | 1050232332555055 |
7 | 53520012355604 |
oct | 7634516056613 |
9 | 1807533822668 |
10 | 536421621131 |
11 | 19754a025530 |
12 | 87b66622a8b |
13 | 3b779a50496 |
14 | 1bd6a46cdab |
15 | de483c98db |
hex | 7ce5385d8b |
536421621131 has 8 divisors (see below), whose sum is σ = 585346588464. Its totient is φ = 487523214720.
The previous prime is 536421621121. The next prime is 536421621143. The reversal of 536421621131 is 131126124635.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 536421621131 - 230 = 535347879307 is a prime.
It is a super-2 number, since 2×5364216211312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 536421621091 and 536421621100.
It is not an unprimeable number, because it can be changed into a prime (536421621121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6597986 + ... + 6678791.
It is an arithmetic number, because the mean of its divisors is an integer number (73168323558).
Almost surely, 2536421621131 is an apocalyptic number.
536421621131 is a deficient number, since it is larger than the sum of its proper divisors (48924967333).
536421621131 is a wasteful number, since it uses less digits than its factorization.
536421621131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13280461.
The product of its digits is 25920, while the sum is 35.
Adding to 536421621131 its reverse (131126124635), we get a palindrome (667547745766).
The spelling of 536421621131 in words is "five hundred thirty-six billion, four hundred twenty-one million, six hundred twenty-one thousand, one hundred thirty-one".
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