Base | Representation |
---|---|
bin | 110001111101110101… |
… | …010011100000111001 |
3 | 12010111000022121222101 |
4 | 301331311103200321 |
5 | 1334334041424423 |
6 | 40351413223401 |
7 | 3606341464345 |
oct | 617565234071 |
9 | 163430277871 |
10 | 53650733113 |
11 | 2083149295a |
12 | a493631b61 |
13 | 50a0203b33 |
14 | 284d528625 |
15 | 15e01287ad |
hex | c7dd53839 |
53650733113 has 4 divisors (see below), whose sum is σ = 53748815440. Its totient is φ = 53552650788.
The previous prime is 53650733107. The next prime is 53650733119. The reversal of 53650733113 is 31133705635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (53650733107) and next prime (53650733119).
It is a cyclic number.
It is not a de Polignac number, because 53650733113 - 229 = 53113862201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53650733119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49040343 + ... + 49041436.
It is an arithmetic number, because the mean of its divisors is an integer number (13437203860).
Almost surely, 253650733113 is an apocalyptic number.
It is an amenable number.
53650733113 is a deficient number, since it is larger than the sum of its proper divisors (98082327).
53650733113 is an equidigital number, since it uses as much as digits as its factorization.
53650733113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98082326.
The product of its (nonzero) digits is 85050, while the sum is 37.
The spelling of 53650733113 in words is "fifty-three billion, six hundred fifty million, seven hundred thirty-three thousand, one hundred thirteen".
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