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5367302113 = 37914161747
BaseRepresentation
bin1001111111110101…
…01000011111100001
3111212001112012100011
410333322220133201
541443012131423
62244331524521
7250002213055
oct47772503741
914761465304
105367302113
11230477a578
1210595b9741
13676c92214
1438cb93c65
1521630bb0d
hex13fea87e1

5367302113 has 4 divisors (see below), whose sum is σ = 5381464240. Its totient is φ = 5353139988.

The previous prime is 5367302111. The next prime is 5367302119. The reversal of 5367302113 is 3112037635.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5367302113 - 21 = 5367302111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5367302111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7080495 + ... + 7081252.

It is an arithmetic number, because the mean of its divisors is an integer number (1345366060).

Almost surely, 25367302113 is an apocalyptic number.

It is an amenable number.

5367302113 is a deficient number, since it is larger than the sum of its proper divisors (14162127).

5367302113 is a wasteful number, since it uses less digits than its factorization.

5367302113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14162126.

The product of its (nonzero) digits is 11340, while the sum is 31.

The square root of 5367302113 is about 73261.8735291420. The cubic root of 5367302113 is about 1750.8623899698.

Adding to 5367302113 its reverse (3112037635), we get a palindrome (8479339748).

The spelling of 5367302113 in words is "five billion, three hundred sixty-seven million, three hundred two thousand, one hundred thirteen".

Divisors: 1 379 14161747 5367302113