Base | Representation |
---|---|
bin | 110010000000111010… |
… | …100011110111000001 |
3 | 12010121121121201211101 |
4 | 302000322203313001 |
5 | 1334440311124213 |
6 | 40400501414401 |
7 | 3610540141363 |
oct | 620072436701 |
9 | 163547551741 |
10 | 53702442433 |
11 | 208586a0932 |
12 | a4a8a0a401 |
13 | 50aab3a273 |
14 | 2856348d33 |
15 | 15e493ebdd |
hex | c80ea3dc1 |
53702442433 has 4 divisors (see below), whose sum is σ = 53725287168. Its totient is φ = 53679597700.
The previous prime is 53702442407. The next prime is 53702442463. The reversal of 53702442433 is 33424420735.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53702442433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53702442392 and 53702442401.
It is not an unprimeable number, because it can be changed into a prime (53702442463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11418841 + ... + 11423542.
It is an arithmetic number, because the mean of its divisors is an integer number (13431321792).
Almost surely, 253702442433 is an apocalyptic number.
It is an amenable number.
53702442433 is a deficient number, since it is larger than the sum of its proper divisors (22844735).
53702442433 is a wasteful number, since it uses less digits than its factorization.
53702442433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22844734.
The product of its (nonzero) digits is 241920, while the sum is 37.
The spelling of 53702442433 in words is "fifty-three billion, seven hundred two million, four hundred forty-two thousand, four hundred thirty-three".
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