5370335315131 has 4 divisors (see below), whose sum is σ = 5373946840032. Its totient is φ = 5366723790232.

The previous prime is 5370335315129. The next prime is 5370335315141. The reversal of 5370335315131 is 1315135330735.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5370335315131 - 2¹ = 5370335315129 is a prime.

It is a super-2 number, since 2×5370335315131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5370335315141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1805760220 + ... + 1805763193.

It is an arithmetic number, because the mean of its divisors is an integer number (1343486710008).

Almost surely, 2^{5370335315131} is an apocalyptic number.

5370335315131 is a deficient number, since it is larger than the sum of its proper divisors (3611524901).

5370335315131 is a wasteful number, since it uses less digits than its factorization.

5370335315131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3611524900.

The product of its (nonzero) digits is 212625, while the sum is 40.

The spelling of 5370335315131 in words is "five trillion, three hundred seventy billion, three hundred thirty-five million, three hundred fifteen thousand, one hundred thirty-one".