Base | Representation |
---|---|
bin | 110010000001110110… |
… | …101100110010100001 |
3 | 12010122201021200122021 |
4 | 302001312230302201 |
5 | 1340003330121044 |
6 | 40402223341441 |
7 | 3611121142201 |
oct | 620166546241 |
9 | 163581250567 |
10 | 53718207649 |
11 | 20866589537 |
12 | a4b2151881 |
13 | 50b1199cb2 |
14 | 2858490401 |
15 | 15e6005e84 |
hex | c81dacca1 |
53718207649 has 16 divisors (see below), whose sum is σ = 55180319040. Its totient is φ = 52266170880.
The previous prime is 53718207601. The next prime is 53718207689. The reversal of 53718207649 is 94670281735.
It is a cyclic number.
It is not a de Polignac number, because 53718207649 - 223 = 53709819041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53718207596 and 53718207605.
It is not an unprimeable number, because it can be changed into a prime (53718207689) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15492414 + ... + 15495880.
It is an arithmetic number, because the mean of its divisors is an integer number (3448769940).
It is a 2-persistent number, because it is pandigital, and so is 2⋅53718207649 = 107436415298, but 3⋅53718207649 = 161154622947 is not.
Almost surely, 253718207649 is an apocalyptic number.
It is an amenable number.
53718207649 is a deficient number, since it is larger than the sum of its proper divisors (1462111391).
53718207649 is a wasteful number, since it uses less digits than its factorization.
With its predecessor (53718207648) it forms a Ruth-Aaron pair, since the sum of their prime factors is the same (4800).
53718207649 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4800.
The product of its (nonzero) digits is 2540160, while the sum is 52.
The spelling of 53718207649 in words is "fifty-three billion, seven hundred eighteen million, two hundred seven thousand, six hundred forty-nine".
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