Base | Representation |
---|---|
bin | 1010000000011100… |
… | …11101011011000011 |
3 | 111212102022021000120 |
4 | 11000032131123003 |
5 | 42000324442101 |
6 | 2245035151323 |
7 | 250064331201 |
oct | 50016353303 |
9 | 14772267016 |
10 | 5372499651 |
11 | 23076aa562 |
12 | 105b2a5543 |
13 | 678091b9c |
14 | 38d748071 |
15 | 2169d6b36 |
hex | 14039d6c3 |
5372499651 has 8 divisors (see below), whose sum is σ = 7208959824. Its totient is φ = 3558852960.
The previous prime is 5372499623. The next prime is 5372499653. The reversal of 5372499651 is 1569942735.
5372499651 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5372499651 - 27 = 5372499523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5372499594 and 5372499603.
It is not an unprimeable number, because it can be changed into a prime (5372499653) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5702820 + ... + 5703761.
It is an arithmetic number, because the mean of its divisors is an integer number (901119978).
Almost surely, 25372499651 is an apocalyptic number.
5372499651 is a deficient number, since it is larger than the sum of its proper divisors (1836460173).
5372499651 is a wasteful number, since it uses less digits than its factorization.
5372499651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11406741.
The product of its digits is 2041200, while the sum is 51.
The square root of 5372499651 is about 73297.3372708723. The cubic root of 5372499651 is about 1751.4273689074.
The spelling of 5372499651 in words is "five billion, three hundred seventy-two million, four hundred ninety-nine thousand, six hundred fifty-one".
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