Base | Representation |
---|---|
bin | 11000011100001100100111… |
… | …11011001011110000011011 |
3 | 21001022000021212012222111221 |
4 | 30032012103323023300123 |
5 | 24021031043312242001 |
6 | 310150144355232511 |
7 | 14214656205265060 |
oct | 1416062373136033 |
9 | 231260255188457 |
10 | 53745407540251 |
11 | 16141332464529 |
12 | 60402782a8737 |
13 | 23cb229b8260b |
14 | d3b41223cc67 |
15 | 633094a4c1a1 |
hex | 30e193ecbc1b |
53745407540251 has 4 divisors (see below), whose sum is σ = 61423322903152. Its totient is φ = 46067492177352.
The previous prime is 53745407540197. The next prime is 53745407540333. The reversal of 53745407540251 is 15204570454735.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53745407540251 - 223 = 53745399151643 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53745407540351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3838957681440 + ... + 3838957681453.
It is an arithmetic number, because the mean of its divisors is an integer number (15355830725788).
Almost surely, 253745407540251 is an apocalyptic number.
53745407540251 is a deficient number, since it is larger than the sum of its proper divisors (7677915362901).
53745407540251 is an equidigital number, since it uses as much as digits as its factorization.
53745407540251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7677915362900.
The product of its (nonzero) digits is 11760000, while the sum is 52.
Adding to 53745407540251 its reverse (15204570454735), we get a palindrome (68949977994986).
The spelling of 53745407540251 in words is "fifty-three trillion, seven hundred forty-five billion, four hundred seven million, five hundred forty thousand, two hundred fifty-one".
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