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53814433 = 195127583
BaseRepresentation
bin1100110101001…
…0010010100001
310202021001112011
43031102102201
5102234030213
65201232521
71222262251
oct315222241
9122231464
1053814433
1128416642
1216032741
13b1c267a
14720b961
154ad003d
hex33524a1

53814433 has 4 divisors (see below), whose sum is σ = 53843968. Its totient is φ = 53784900.

The previous prime is 53814421. The next prime is 53814463. The reversal of 53814433 is 33441835.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53814433 - 225 = 20260001 is a prime.

It is a super-2 number, since 2×538144332 = 5791986398222978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53814395 and 53814404.

It is not an unprimeable number, because it can be changed into a prime (53814463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11841 + ... + 15742.

It is an arithmetic number, because the mean of its divisors is an integer number (13460992).

Almost surely, 253814433 is an apocalyptic number.

It is an amenable number.

53814433 is a deficient number, since it is larger than the sum of its proper divisors (29535).

53814433 is a wasteful number, since it uses less digits than its factorization.

53814433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29534.

The product of its digits is 17280, while the sum is 31.

The square root of 53814433 is about 7335.8321273050. The cubic root of 53814433 is about 377.5428555355.

The spelling of 53814433 in words is "fifty-three million, eight hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 1951 27583 53814433