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53850113 = 79681647
BaseRepresentation
bin1100110101101…
…1000000000001
310202022212110122
43031123000001
5102241200423
65202110025
71222501262
oct315330001
9122285418
1053850113
1128440429
121604b315
13b205995
14721a969
154ada8c8
hex335b001

53850113 has 4 divisors (see below), whose sum is σ = 54531840. Its totient is φ = 53168388.

The previous prime is 53850103. The next prime is 53850127. The reversal of 53850113 is 31105835.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53850113 - 214 = 53833729 is a prime.

It is a super-2 number, since 2×538501132 = 5799669340225538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53850103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340745 + ... + 340902.

It is an arithmetic number, because the mean of its divisors is an integer number (13632960).

Almost surely, 253850113 is an apocalyptic number.

It is an amenable number.

53850113 is a deficient number, since it is larger than the sum of its proper divisors (681727).

53850113 is an equidigital number, since it uses as much as digits as its factorization.

53850113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 681726.

The product of its (nonzero) digits is 1800, while the sum is 26.

The square root of 53850113 is about 7338.2636229560. The cubic root of 53850113 is about 377.6262764836.

Adding to 53850113 its reverse (31105835), we get a palindrome (84955948).

The spelling of 53850113 in words is "fifty-three million, eight hundred fifty thousand, one hundred thirteen".

Divisors: 1 79 681647 53850113