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539085403 = 1432137643
BaseRepresentation
bin100000001000011…
…100101001011011
31101120101101011001
4200020130221123
52101001213103
6125254245431
716234102363
oct4010345133
91346341131
10539085403
1125733292a
12130656877
13878bb55c
145184b9a3
15324d901d
hex2021ca5b

539085403 has 4 divisors (see below), whose sum is σ = 539137368. Its totient is φ = 539033440.

The previous prime is 539085397. The next prime is 539085451. The reversal of 539085403 is 304580935.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 539085403 - 229 = 2214491 is a prime.

It is a super-2 number, since 2×5390854032 = 581226143455344818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (539082403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4501 + ... + 33142.

It is an arithmetic number, because the mean of its divisors is an integer number (134784342).

Almost surely, 2539085403 is an apocalyptic number.

539085403 is a deficient number, since it is larger than the sum of its proper divisors (51965).

539085403 is a wasteful number, since it uses less digits than its factorization.

539085403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51964.

The product of its (nonzero) digits is 64800, while the sum is 37.

The square root of 539085403 is about 23218.2127434478. The cubic root of 539085403 is about 813.8652847711.

The spelling of 539085403 in words is "five hundred thirty-nine million, eighty-five thousand, four hundred three".

Divisors: 1 14321 37643 539085403