Base | Representation |
---|---|
bin | 11000100001000100011100… |
… | …10101100010001111010011 |
3 | 21001220000101221121120011010 |
4 | 30100202032111202033103 |
5 | 24031301422240244311 |
6 | 310355112332022003 |
7 | 14233033606452504 |
oct | 1420421625421723 |
9 | 231800357546133 |
10 | 53912817509331 |
11 | 161a632aa86080 |
12 | 60687b9601903 |
13 | 2410c59347211 |
14 | d45573d0abab |
15 | 6375e1cd5da6 |
hex | 31088e5623d3 |
53912817509331 has 8 divisors (see below), whose sum is σ = 78418643649984. Its totient is φ = 32674434854120.
The previous prime is 53912817509329. The next prime is 53912817509363. The reversal of 53912817509331 is 13390571821935.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53912817509331 - 21 = 53912817509329 is a prime.
It is a super-2 number, since 2×539128175093312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53912817509371) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 816860871321 + ... + 816860871386.
It is an arithmetic number, because the mean of its divisors is an integer number (9802330456248).
Almost surely, 253912817509331 is an apocalyptic number.
53912817509331 is a deficient number, since it is larger than the sum of its proper divisors (24505826140653).
53912817509331 is a wasteful number, since it uses less digits than its factorization.
53912817509331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1633721742721.
The product of its (nonzero) digits is 6123600, while the sum is 57.
The spelling of 53912817509331 in words is "fifty-three trillion, nine hundred twelve billion, eight hundred seventeen million, five hundred nine thousand, three hundred thirty-one".
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