Base | Representation |
---|---|
bin | 110010001101011110… |
… | …101100110000110001 |
3 | 12011011022021111101200 |
4 | 302031132230300301 |
5 | 1340403242231143 |
6 | 40433431521413 |
7 | 3616010000343 |
oct | 621536546061 |
9 | 164138244350 |
10 | 53913242673 |
11 | 20956690204 |
12 | a547529269 |
13 | 5112706434 |
14 | 287633d293 |
15 | 16081ce1d3 |
hex | c8d7acc31 |
53913242673 has 6 divisors (see below), whose sum is σ = 77874683874. Its totient is φ = 35942161776.
The previous prime is 53913242671. The next prime is 53913242681. The reversal of 53913242673 is 37624231935.
53913242673 is a `hidden beast` number, since 539 + 1 + 3 + 2 + 42 + 6 + 73 = 666.
53913242673 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 50340550689 + 3572691984 = 224367^2 + 59772^2 .
It is not a de Polignac number, because 53913242673 - 21 = 53913242671 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53913242671) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2995180140 + ... + 2995180157.
It is an arithmetic number, because the mean of its divisors is an integer number (12979113979).
Almost surely, 253913242673 is an apocalyptic number.
It is an amenable number.
53913242673 is a deficient number, since it is larger than the sum of its proper divisors (23961441201).
53913242673 is a wasteful number, since it uses less digits than its factorization.
53913242673 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5990360303 (or 5990360300 counting only the distinct ones).
The product of its digits is 816480, while the sum is 45.
The spelling of 53913242673 in words is "fifty-three billion, nine hundred thirteen million, two hundred forty-two thousand, six hundred seventy-three".
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