Base | Representation |
---|---|
bin | 100000001011111… |
… | …110101110101001 |
3 | 1101122010102102110 |
4 | 200023332232221 |
5 | 2101220331213 |
6 | 125330152533 |
7 | 16245010233 |
oct | 4013765651 |
9 | 1348112373 |
10 | 540011433 |
11 | 257905645 |
12 | 130a22749 |
13 | 87b53bc0 |
14 | 51a0d253 |
15 | 3261d5c3 |
hex | 202feba9 |
540011433 has 16 divisors (see below), whose sum is σ = 776635776. Its totient is φ = 331785600.
The previous prime is 540011419. The next prime is 540011453. The reversal of 540011433 is 334110045.
It is not a de Polignac number, because 540011433 - 25 = 540011401 is a prime.
It is a super-2 number, since 2×5400114332 = 583224695541426978, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (540011453) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14533 + ... + 35933.
It is an arithmetic number, because the mean of its divisors is an integer number (48539736).
Almost surely, 2540011433 is an apocalyptic number.
It is an amenable number.
540011433 is a deficient number, since it is larger than the sum of its proper divisors (236624343).
540011433 is a wasteful number, since it uses less digits than its factorization.
540011433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22064.
The product of its (nonzero) digits is 720, while the sum is 21.
The square root of 540011433 is about 23238.1460749346. The cubic root of 540011433 is about 814.3310319632.
Adding to 540011433 its reverse (334110045), we get a palindrome (874121478).
The spelling of 540011433 in words is "five hundred forty million, eleven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.595 sec. • engine limits •