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540100121 = 1149100011
BaseRepresentation
bin100000001100010…
…100011000011001
31101122021221002012
4200030110120121
52101231200441
6125332115305
716245526631
oct4014243031
91348257065
10540100121
11257966240
12130a65b35
1387b85392
1451a336c1
15326399eb
hex20314619

540100121 has 4 divisors (see below), whose sum is σ = 589200144. Its totient is φ = 491000100.

The previous prime is 540100103. The next prime is 540100151. The reversal of 540100121 is 121001045.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-540100121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 540100096 and 540100105.

It is not an unprimeable number, because it can be changed into a prime (540100151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24549995 + ... + 24550016.

It is an arithmetic number, because the mean of its divisors is an integer number (147300036).

Almost surely, 2540100121 is an apocalyptic number.

It is an amenable number.

540100121 is a deficient number, since it is larger than the sum of its proper divisors (49100023).

540100121 is a wasteful number, since it uses less digits than its factorization.

540100121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49100022.

The product of its (nonzero) digits is 40, while the sum is 14.

The square root of 540100121 is about 23240.0542383188. The cubic root of 540100121 is about 814.3756096843.

Adding to 540100121 its reverse (121001045), we get a palindrome (661101166).

The spelling of 540100121 in words is "five hundred forty million, one hundred thousand, one hundred twenty-one".

Divisors: 1 11 49100011 540100121