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54011114011 = 349154759639
BaseRepresentation
bin110010010011010100…
…000011001000011011
312011102010102212122001
4302103110003020123
51341103321122021
640451245341431
73621305615461
oct622324031033
9164363385561
1054011114011
11209a6958408
12a574267877
135129a8307a
142885338831
151611ab3091
hexc9350321b

54011114011 has 4 divisors (see below), whose sum is σ = 54165874000. Its totient is φ = 53856354024.

The previous prime is 54011113987. The next prime is 54011114023. The reversal of 54011114011 is 11041111045.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11041111045 = 52208222209.

It is a cyclic number.

It is not a de Polignac number, because 54011114011 - 217 = 54010982939 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 54011114011.

It is not an unprimeable number, because it can be changed into a prime (54011114041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77379471 + ... + 77380168.

It is an arithmetic number, because the mean of its divisors is an integer number (13541468500).

Almost surely, 254011114011 is an apocalyptic number.

54011114011 is a deficient number, since it is larger than the sum of its proper divisors (154759989).

54011114011 is a wasteful number, since it uses less digits than its factorization.

54011114011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154759988.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 54011114011 its reverse (11041111045), we get a palindrome (65052225056).

The spelling of 54011114011 in words is "fifty-four billion, eleven million, one hundred fourteen thousand, eleven".

Divisors: 1 349 154759639 54011114011