540125433 has 6 divisors (see below), whose sum is σ = 780181194. Its totient is φ = 360083616.

The previous prime is 540125429. The next prime is 540125437. The reversal of 540125433 is 334521045.

540125433 is a `hidden beast` number, since 5 + 401 + 254 + 3 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (540125429) and next prime (540125437).

It can be written as a sum of positive squares in only one way, i.e., 338854464 + 201270969 = 18408^2 + 14187^2 .

It is not a de Polignac number, because 540125433 - 2² = 540125429 is a prime.

It is a super-3 number, since 3×540125433³ (a number of 27 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 540125397 and 540125406.

It is not an unprimeable number, because it can be changed into a prime (540125437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 30006960 + ... + 30006977.

It is an arithmetic number, because the mean of its divisors is an integer number (130030199).

Almost surely, 2^540125433 is an apocalyptic number.

It is an amenable number.

540125433 is a deficient number, since it is larger than the sum of its proper divisors (240055761).

540125433 is a wasteful number, since it uses less digits than its factorization.

540125433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60013943 (or 60013940 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 27.

The square root of 540125433 is about 23240.5988089808. The cubic root of 540125433 is about 814.3883314944.

Adding to 540125433 its reverse (334521045), we get a palindrome (874646478).

The spelling of 540125433 in words is "five hundred forty million, one hundred twenty-five thousand, four hundred thirty-three".