54014666113 has 4 divisors (see below), whose sum is σ = 54015268608. Its totient is φ = 54014063620.

The previous prime is 54014666107. The next prime is 54014666119. The reversal of 54014666113 is 31166641045.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31166641045 = 5 ⋅6233328209.

It is an interprime number because it is at equal distance from previous prime (54014666107) and next prime (54014666119).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-54014666113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54014666119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136873 + ... + 356038.

It is an arithmetic number, because the mean of its divisors is an integer number (13503817152).

Almost surely, 2^54014666113 is an apocalyptic number.

It is an amenable number.

54014666113 is a deficient number, since it is larger than the sum of its proper divisors (602495).

54014666113 is a wasteful number, since it uses less digits than its factorization.

54014666113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 602494.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 54014666113 in words is "fifty-four billion, fourteen million, six hundred sixty-six thousand, one hundred thirteen".