Base | Representation |
---|---|
bin | 110010010011111111… |
… | …100100001001011001 |
3 | 12011102220220102200011 |
4 | 302103333210021121 |
5 | 1341114231141213 |
6 | 40452334041521 |
7 | 3621504566326 |
oct | 622377441131 |
9 | 164386812604 |
10 | 54022521433 |
11 | 20a02339a31 |
12 | a5780492a1 |
13 | 512c24841a |
14 | 2886a67b4d |
15 | 1612ab803d |
hex | c93fe4259 |
54022521433 has 4 divisors (see below), whose sum is σ = 54023393188. Its totient is φ = 54021649680.
The previous prime is 54022521407. The next prime is 54022521437. The reversal of 54022521433 is 33412522045.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 52277621449 + 1744899984 = 228643^2 + 41772^2 .
It is a cyclic number.
It is not a de Polignac number, because 54022521433 - 213 = 54022513241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54022521395 and 54022521404.
It is not an unprimeable number, because it can be changed into a prime (54022521437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335166 + ... + 469447.
It is an arithmetic number, because the mean of its divisors is an integer number (13505848297).
Almost surely, 254022521433 is an apocalyptic number.
It is an amenable number.
54022521433 is a deficient number, since it is larger than the sum of its proper divisors (871755).
54022521433 is an equidigital number, since it uses as much as digits as its factorization.
54022521433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 871754.
The product of its (nonzero) digits is 28800, while the sum is 31.
The spelling of 54022521433 in words is "fifty-four billion, twenty-two million, five hundred twenty-one thousand, four hundred thirty-three".
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