Base | Representation |
---|---|
bin | 11000100100011111101010… |
… | …11000101101010011110001 |
3 | 21002022021012011202112100201 |
4 | 30102033311120231103301 |
5 | 24040213441142330340 |
6 | 310525135053315201 |
7 | 14244401263456324 |
oct | 1422176530552361 |
9 | 232267164675321 |
10 | 54030510511345 |
11 | 1624123567a495 |
12 | 6087584795b01 |
13 | 241c0945a9104 |
14 | d4b13aac27bb |
15 | 63a6ce48679a |
hex | 3123f562d4f1 |
54030510511345 has 16 divisors (see below), whose sum is σ = 66762128138832. Its totient is φ = 41951656304640.
The previous prime is 54030510511333. The next prime is 54030510511361. The reversal of 54030510511345 is 54311501503045.
It can be written as a sum of positive squares in 8 ways, for example, as 5169907230049 + 48860603281296 = 2273743^2 + 6990036^2 .
It is not a de Polignac number, because 54030510511345 - 213 = 54030510503153 is a prime.
It is a super-2 number, since 2×540305105113452 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 682767342 + ... + 682846471.
It is an arithmetic number, because the mean of its divisors is an integer number (4172633008677).
Almost surely, 254030510511345 is an apocalyptic number.
It is an amenable number.
54030510511345 is a deficient number, since it is larger than the sum of its proper divisors (12731617627487).
54030510511345 is a wasteful number, since it uses less digits than its factorization.
54030510511345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1365614052.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 54030510511345 in words is "fifty-four trillion, thirty billion, five hundred ten million, five hundred eleven thousand, three hundred forty-five".
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