Base | Representation |
---|---|
bin | 100111010011111111011… |
… | …1101111110010110110011 |
3 | 201010112012221201022020020 |
4 | 1032213332331332112303 |
5 | 1202010422144101011 |
6 | 15254043322014523 |
7 | 1065233440260564 |
oct | 116477675762663 |
9 | 21115187638206 |
10 | 5403051550131 |
11 | 17a346a819714 |
12 | 733193047443 |
13 | 302675995971 |
14 | 14971ad3016b |
15 | 9582be93006 |
hex | 4e9fef7e5b3 |
5403051550131 has 8 divisors (see below), whose sum is σ = 7211757177744. Its totient is φ = 3598190144640.
The previous prime is 5403051550121. The next prime is 5403051550157. The reversal of 5403051550131 is 1310551503045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5403051550131 - 29 = 5403051549619 is a prime.
It is a super-2 number, since 2×54030515501312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5403051550092 and 5403051550101.
It is not an unprimeable number, because it can be changed into a prime (5403051550121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 961052250 + ... + 961057871.
It is an arithmetic number, because the mean of its divisors is an integer number (901469647218).
Almost surely, 25403051550131 is an apocalyptic number.
5403051550131 is a deficient number, since it is larger than the sum of its proper divisors (1808705627613).
5403051550131 is a wasteful number, since it uses less digits than its factorization.
5403051550131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1922111061.
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 5403051550131 in words is "five trillion, four hundred three billion, fifty-one million, five hundred fifty thousand, one hundred thirty-one".
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