Base | Representation |
---|---|
bin | 111101011011100000111101… |
… | …0100000111111110100001001 |
3 | 2121212012022111200222201010112 |
4 | 1322313001322200333310021 |
5 | 1031310441040031424023 |
6 | 5153114141410524105 |
7 | 221546341501663220 |
oct | 17267017240776411 |
9 | 2555168450881115 |
10 | 540343301045513 |
11 | 1471963417a0569 |
12 | 5072a19a296635 |
13 | 1a2672019c9774 |
14 | 9760a80813cb7 |
15 | 42708814bd478 |
hex | 1eb707a83fd09 |
540343301045513 has 16 divisors (see below), whose sum is σ = 626834388787584. Its totient is φ = 456178824414720.
The previous prime is 540343301045501. The next prime is 540343301045519. The reversal of 540343301045513 is 315540103343045.
It is a cyclic number.
It is not a de Polignac number, because 540343301045513 - 210 = 540343301044489 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (540343301045519) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72014120 + ... + 79162617.
It is an arithmetic number, because the mean of its divisors is an integer number (39177149299224).
Almost surely, 2540343301045513 is an apocalyptic number.
It is an amenable number.
540343301045513 is a deficient number, since it is larger than the sum of its proper divisors (86491087742071).
540343301045513 is a wasteful number, since it uses less digits than its factorization.
540343301045513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151184432.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 540343301045513 its reverse (315540103343045), we get a palindrome (855883404388558).
The spelling of 540343301045513 in words is "five hundred forty trillion, three hundred forty-three billion, three hundred one million, forty-five thousand, five hundred thirteen".
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